Person
.+----+---------+ | Id | Email | +----+---------+ | 1 | a@b.com | | 2 | c@d.com | | 3 | a@b.com | +----+---------+For example, your query should return the following for the above table:
+---------+ | Email | +---------+ | a@b.com | +---------+Note: All emails are in lowercase.
Naive Way: 我先建一个Table(Email, count(*)), 然后在这个Table里找count(*) > 1的。
SELECT Email
FROM
(SELECT Email, count(*) AS num
FROM Person
FROUP BY Email) E
WHERE num > 1;
Improved Way: 不需要使用多余的subquery。
SELECT Email from Person
GROUP BY Email
HAVING count(Email)>1;
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