Employee
table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+Given the
Employee
table, write a SQL query that finds
out employees who earn more than their managers. For the above table,
Joe is the only employee who earns more than his manager.+----------+ | Employee | +----------+ | Joe | +----------+
Naive Way: 这回一次就过了。
SELECT E1.Name AS Employee
FROM Employee E1 join Employee E2
WHERE E1.ManagerId = E2.Id AND E1.Salary > E2.Salary;
Improved Way:还有用left join 的,来自
SELECT e1.`Name`
FROM `Employee` e1
LEFT JOIN `Employee` e2 ON(e2.`Id` = e1.`ManagerId`)
WHERE e1.`ManagerId` IS NOT NULL AND e1.`Salary` > e2.`Salary`
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